Topics

https://docs.python.org/3/reference/lexical_analysis.html

function parameters

 # 1️⃣ *args — Extra positional parameters

def print_numbers(*args):

    print("Positional numbers:", args)

print_numbers(1, 2, 3, 4)

# Output:

# Positional numbers: (1, 2, 3, 4)

print()

# 2️⃣ **kwargs — Extra keyword parameters

def print_info(**kwargs):

    print("Keyword info:", kwargs)

print_info(name="Alice", age=17, country="FR")

# Output:

# Keyword info: {'name': 'Alice', 'age': 17, 'country': 'FR'}

print()

# 3️⃣ * — Force keyword-only arguments

def connect(host, port, *, timeout=5, ssl=False):

    print(host, port, timeout, ssl)

connect("localhost", 5432, timeout=10, ssl=True)

# Output:

# localhost 5432 10 True

print()

# 4️⃣ ** in a call — Unpack dict into keywords

def greet(name, age):

    print(f"Hello {name}, you are {age} years old!")

data = {"name": "Bob", "age": 20}

greet(**data)

# Output:

# Hello Bob, you are 20 years old!

print()

# 5️⃣ Combined example with all of them

def full_example(a, b, *args, c=10, **kwargs):

    print("a, b:", a, b)

    print("args:", args)

    print("c:", c)

    print("kwargs:", kwargs)

full_example(1, 2, 3, 4, 5, c=99, x=100, y=200)

# Output:

# a, b: 1 2

# args: (3, 4, 5)

# c: 99

# kwargs: {'x': 100, 'y': 200}

iterating

 >>> i=0

>>> while i<len(a.keys()):

...    print(a[list(a.keys())[i]])

...    i=i+1

... 

Ambiorix

43

195

---------

for key in a:

    print(a[key])

-------------

for value in a.values():

    print(value)

Pyhon Exception

 try:

    result = 10 / a

except Exception as e:

    print(f"An unexpected error occurred: {e}")

else:

    print("Codigo funciona")

finally:

    print("Siempre corre")

python generators

# Online Python compiler (interpreter) to run Python online.

# Write Python 3 code in this online editor and run it.

def  test(i):

    n=0

    while n<i:

        if n==3:

            yield 'We reached the limit'

        else:

            

          yield n

        n=n+1

m=test(24)

print(next(m))

print(next(m))

print(next(m))

print(next(m))

///////

0

1

2

We reached the limit

while and if

 i=0

m=True

while m:

    print(i)

    i+=1

    if i==10:

        m=False

0

1

2

3

4

5

6

7

8

9

find missing number from a list range

 l1=[1,2,5,6]

l2=[7, 1, 3, 5, 6]

def find_missing_number(l1):

    max_n=max(l1)+1

    min_n=min(l1) 

    c=[a for a in range(min_n,max_n) ]

    missing_n=[a for a in c if a not in l1]

    return missing_n

print(find_missing_number(l1))

print(find_missing_number(l2))

[3, 4]

[2, 4]